[1-(6+3a)/(a2+4a+4)]÷[(4a-4)/(a2+2a)] [1-(6+3a)/(a²+4a+4)]÷[_数学解答

[1-(6+3a)/(a2+4a+4)]÷[(4a-4)/(a2+2a)]
[1-(6+3a)/(a²+4a+4)]÷[(4a-4)/(a²+2a)]
a2是a的平方的意思

人气：373 ℃　时间：2020-04-09 13:28:18

解答

原式=(a²+4a+4-6-3a)/(a²+4a+4)×(a²+2a)/(4a-4)
=(a+2)(a-1)/(a+2)²×a(a+2)/4(a-1)
=a/4