已知x=156,y=144,求代数式
x2+xy+y2的值.
人气:237 ℃ 时间:2019-08-18 08:02:49
解答
x2+xy+y2=
(x
2+2xy+y
2)
=
(x+y)
2,
当x=156,y=144时,
原式=
(156+144)
2=45000.
推荐
猜你喜欢
- 3.-----------,state television could become much more popular.A.Giving enough money B.Given enough
- 在直角坐标系中,A(1,0);B(-1,0),△ABC为等腰三角形,则C点的坐标为?
- 氯乙烯原子都在同一平面吗?
- my home is about two kilometers from school(对划线部分提问) about two kilometers
- 设M是三角形ABC内一点,且向量AB*向量AC=(2根号3),角BAC=30度,定义f(M)=(m,n,p),其中
- While I ------(cross) the street,I ------(hear) someone -----(call) me.
- 单调增函数和单调减函数的定义~
- 在一个减法算式中,被减数减少30,减数增加30,差就_.