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(1)某商品连续两次提价10%,又提价5%,要恢复原价,至少应降价x%(x为整数),x=( )
人气:480 ℃ 时间:2020-04-11 03:25:40
解答
设原来价格A,则[A(1+10%)(1+10%)(1+5%)-A]/A(1+10%)(1+10%)(1+5%) =21%能否详细点用一元一次方程[A(1+10%)(1+10%)(1+5%)-A]/A(1+10%)(1+10%)(1+5%) =X% ,A是可以约去的,X=[(1+10%)(1+10%)(1+5%)-1]/(1+10%)(1+10%)(1+5%) *100=21我还是不懂怎么得的21[A(1+10%)(1+10%)(1+5%)-A]/A(1+10%)(1+10%)(1+5%) =X% ,A是可以约去的,X=[(1+10%)(1+10%)(1+5%)-1]/(1+10%)(1+10%)(1+5%) *100=[(1.1*1.1*1.05-1)/(1.1*1.1*1.05)]*100=[(1.2705-1)/1.2705]*100=(0.2705/1.2705)*100=0.2129*100=21题目上要求整数,所以21是约等于得出来的
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