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3x²-6x+2=0的配方过程
求此题配方过程
人气:213 ℃ 时间:2020-05-27 19:05:09
解答
3x²-6x+2=0
x²-2x+2/3=0
x²-2x+4-4+2/3=0
(x-2)²-10/3=0
x-2=±√(10/3)=±(√30)/3我这答案是1正负根号3/3配方中出现错误,现更正3x²-6x+2=0x²-2x+2/3=0x²-2x+1-1+2/3=0(x-1)²-1/3=0x-1=±√(1/3)x=1±(√3)/3
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