6x²+mxy-3y²+3x+10y-3=6x²+(my+3)x-(3y²-10y+3)=6x²+(my+3)x+(3y-1)(3-y)按“双十字相乘法”若能“凑”成中间项,必须是原式=[x-(3y-1)][6x-(3-y)]=6x²+(3-17y)x+(3y-1)(3-y) 或原式=[...