| 1 |
| xlna |
∵h(x)=f(x)-g(x)在定义域上为减函数
∴h′(x)≤0在(0,+∞)上恒成立即
| 1 |
| lna |
即
| 1 |
| lna |
令u(x)=-x2+2x=-(x-1)2+1≤1
∴
| 1 |
| lna |
∵h′(x)存在零点
∴x2−2x+
| 1 |
| lna |
∴△=4(1−
| 1 |
| lna |
∴
| 1 |
| lna |
∴lna=1即a=e
(II)∵g(x)=lnx,p(x)=ex
令F(x)=ex(x−x2)−ex+ex2(x<x2)
F′(x)=ex+exx-x2ex-ex=(x-x2)ex<0
∴F(x)在(-∞,x2)上递减
∴ex1(x1−x2)>ex1−ex2
即ex1<
| ex1−ex2 |
| x1−x2 |
同理
| ex1−ex2 |
| x1−x2 |
所以有P(x1)<P(x0)<P(x2)
