我明白你的问题了.设这个奇数是2n+1,则(2n+1)^2=4n^2+4n+1=(2n^2+2n)+(2n^2+2n+1)现在就是要证明：(2n^2+2n)＾2+(2n+1)^2＝(2n^2+2n+1)＾2(2n^2+2n)＾2+(2n+1)^2＝(2n^2+2n)＾2+4n^2+4n+1＝(2n^2+2n)＾2+2（2n^2+2n...