(x+1)/x^2-2x^2/(x+1)=1
令a=(x+1)/x^2,则x^2/(x+1)=1/a
a-2/a-1=0
a^2-a-2=0
(a-2)(a+1)=0
a=2,a=-1
a=2
(x+1)/x^2=2
2x^2-x-1=0
(2x+1)(x-1)=0
x=-1/2,x=1
a=-1
(x+1)/x^2=-1
x^2+x+1=0
无解
所以x1=-1/2,x2=1