已知tanx=1/3,tany=-2,且0
人气：411 ℃ 时间：2020-06-02 18:59:34
解答
tan(x+y)=(tanx+tany)/(1-tanx*tany)=(1/3-2)/(1-(1/3)*(-2))
=-1
又0
推荐
- tanx=1/2,x=?tany=1/3,y=?
- 已知tanx=2,tany=3,x,y∈(0,π/2),求x+y.
- 已知sin(x+y)=1/2,sin(x-y)=1/3,求tanx,tany
- 已知tanx=2,tany=1/3,则tan2(x+y)=
- 若0
- How often do you get this magazine?
- 初一英语50词作文两篇
- 英语完形填空,看不懂
猜你喜欢
