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若x满足不等式2(log0.5x)∧2+7log0.5x+3≤0,则f(x)=log0.5(x/2)log0.5(x/4)的最值?
人气:159 ℃ 时间:2020-06-24 14:49:59
解答
2(log0.5x)∧2+7log0.5x+3≤0[2(log0.5x)+1]*[(log0.5x)+3]≤0-3≤(log0.5x)≤-1/2log0.5(x/2)log0.5(x/4)=[(log0.5x)+1]*[(log0.5x)+2]=(log0.5x)∧2+3log0.5x+21/4≤(log0.5x)∧2+3log0.5x+2≤2f(x)=log0.5(x/2)lo...
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