6（y+2）/(y+2)²-(y+2)(y-2)/(y-2)²+y²/(y+2)（y-2）=0
6/(y+2)-(y+2)/(y-2)+y²/(y+2)（y-2）=0
6(y-2)-（y+2)²+y²=0
6y-12-4y-4=0
y=8额，呵呵，你算错了吧，答案是8，不过谢谢你回答我的求助问题，谢谢。o(∩_∩)o是8啊，你刷新看看，我在你追前就改了哦