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先化简,再求值:(1)(x+1/x²-x-x/x²-2x+1)÷1/x,x=根号2+1
(2)(1+x-3/x+3)÷2x/x²-9 x=根号3+3 (3)4-x/x-2÷(x+2-12/x-2)x=根号3-4 (4)x-3/2x-4÷(5/x-2-x-2) x=根号3-2
人气:340 ℃ 时间:2019-11-15 16:35:31
解答
先化简,再求值:(1)(x+1/x²-x-x/x²-2x+1)÷1/x,x=根号2+1 急!=((x+1)/x(x-1)-x/(x-1)²)×x=(x+1)/(x-1)-x²/(x-1)²=(x²-1-x²)/(x-1)²=-1/(√2+1-1)²=-1/2;(2)(1...
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