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急 [ln^3(x^2)+3]' 求导
人气:408 ℃ 时间:2020-04-16 17:15:36
解答
令a=ln(x^2)
则先对a^3求导,再对ln求导,最后对x^2求导
所以[ln^3(x^2)+3]'
=[ln^3(x^2)]'
=3[ln(x^2)]^2*[ln(x^2)]'
=3[ln(x^2)]^2*(1/x^2)*(x^2)'
=6x[ln(x^2)]^2*(1/x^2)
=(6/x)*[ln(x^2)]^2
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