f(x)=sin^2(x)+acosx-0.5=[1-cos^2(x)]+acosx-0.5=-cos^2(x)+acosx+1/2=-(cosx-a/2)^2+(a^2+2)/4由于X属于[0,360度]则:cosx属于[-1,1]则:(1)当a/2>=1时,a>=2则:cosx=1时,f(x)=1-(1-a/2)^2+(a^2+2)/4=1a=3/2又a>=2,则...