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把下列各式分解因式 x(x+y)(x-y)-x(y+x)² 2 已知2x+y=6,x-3y=1,求7y(x-3y)²
把下列各式分解因式
x(x+y)(x-y)-x(y+x)²
7、已知2x+y=6,x-3y=1,求7y(x-3y)²-2(3y-x)³的值
人气:397 ℃ 时间:2020-04-07 19:15:05
解答
x(x+y)(x-y)-x(y+x)^2=x(x+y)(x-y)-x(x+y)^2=x(x+y){(x-y)-(x+y)}=2xy(x+y)7y(x-3y)^2-2(3y-x)^3=7y(x-3y)^2 +2(x-3y)^3={7y+2(x-3y)}(x-3y)^2=(2x+y)(x-3y)^2=6x1^2=6
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