f(x)=sin(2x+π/6)+sin(2x+π/6)+cos2x
=2sin(2x+π/6)+cos2x
=2[sin2xcosπ/6+cos2xsinπ/6]+cos2x
=√3sin2x+cos2x+cos2x
=√3sin2x+2cos2x
函数y=f(x)的最小正周期
最小正周期：π