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用适当的方法解方程.(1)25x²-36=0 (2)(x²-x)²-(x²-x)-2=0
人气:467 ℃ 时间:2020-04-04 22:46:41
解答
您好:(1)25x²-36=0 (5x+6)(5x-6)=0x1=-6/5x2=6/5(2)(x²-x)²-(x²-x)-2=0(x²-x-2)(x²-x+1)=0(x-2)(x+1)(x²-x+1)=0x1=2x2=-1不明白,可以追问如有帮助,记得采纳,谢谢 ...
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