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帮帮哦,原题是这样的:
sin(540-x)/tan(900-x) 乘以 1/tan(450-x)tan(810-x) 乘以 cos(360-x)/sin(-x)
条件是tanx=2
我怎么化简都是得sinx,真是邪门了,
人气:423 ℃ 时间:2020-06-18 21:30:16
解答
原式是这样吧?sin(540-x)/tan(900-x) *1/(tan(450-x)tan(810-x) ) *cos(360-x)/sin(-x)sin(540-x)=sin(180-x)=sinxtan(900-x)=tan(-x)=-tanxtan(450-x)=tan(90-x)=cotxtan(810-x)=tan(90-x)=cotxcos(360-x)=cos(-x)=...
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