化简cos(180°+x)*sin(x+360°)/[sin(-x-180°)*cos(-180°-x)]_数学解答

化简cos(180°+x)*sin(x+360°)/[sin(-x-180°)*cos(-180°-x)]

人气：171 ℃　时间：2020-03-21 19:56:17

解答

cos(180°+x)*sin(x+360°)/[sin(-x-180°)*cos(-180°-x)]
=-cosx×sinx/[-sin(180°+x)][cos(180°+x)]
=-cosx×sinx/sinx(-cosx)
=1