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因式分解:4x^4-x^2+2x-1
人气:258 ℃ 时间:2020-01-31 11:38:37
解答
4x^4-x^2+2x-1
=x^2(4x^2-1)+(2x-1)
=x^2(2x+1)(2x-1)+(2x-1)
=(2x-1)[x^2(2x+1)+1]
=(2x-1)(2x^3+x^2+1)
=(2x-1)(2x^3+x^2+2x-2x+1)
=(2x-1)[(2x^3-2x)+(x^2+2x+1)]
=(2x-1)[2x(x^2-1)+(x+1)^2]
=(2x-1)[2x(x+1)(x-1)+(x+1)^2]
=(2x-1){(x+1)[2x(x-1)+x+1}
=(2x-1)[(x+1)(2x^2-2x+x+1)
=(2x-1)(x+1)(2x^2-x+1)
如果楼主是在实数范围内分解,到此步可以停止;
若是复数可继续分解.
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