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求下列函数值域,
①y﹦cosx②y﹦cosx,x∈[-π/2,π/2]③y﹦cosx,x∈[-π/3,π]④y﹦2sin(2x-π/3)﹢1⑤y﹦2sin(2x-π/3)﹢1,x∈[π/3,π]
人气:399 ℃ 时间:2020-08-09 13:03:08
解答
①y﹦cosx值域为[-1,1]②y﹦cosx,x∈[-π/2,π/2]值域为[0,1]③y﹦cosx,x∈[-π/3,π]值域为[-1,1]④y﹦2sin(2x-π/3)﹢1值域为[-1,3]⑤y﹦2sin(2x-π/3)﹢1,x∈[π/3,π]2x-π/3的范围为 [π/3,5π/3]所以 2sin...
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