f=lg[(kx-1)/(x-1)]设真数t=(kx-1)/(x-1)>0函数f在【10,正无穷）上单调递增需t=(kx-1)/(x-1)在【10,正无穷）上单调递增k=0时,t=1/(1-x) 定义域为(-∞,1)不合题意t=[(kx-k)+(k-1)]/(x-1)=k+(k-1)/(x-1)k>1时,t=k+(k-1...