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dy/dx=3x^2-8x+100 求y=?
人气:311 ℃ 时间:2020-04-06 08:39:20
解答
y=x^3-4x^2+100x跪求步骤三个分开,一个一个来d(x^3)/dx=3x^2d(x^2)/dx=2xdx/dx=1所以dy/dx=d(x^3)/dx-4*[d(x^2)/dx]+100*(dx/dx)dy=d(x^3)-4*d(x^2)+100*dx=d(x^3-4x^2+100x )y=x^3-4x^2+100x
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