解不等式:(2x-3)(x-4)-(x+2)(x-3)≥x^2-8_数学解答

解不等式:(2x-3)(x-4)-(x+2)(x-3)≥x^2-8

人气：468 ℃　时间：2020-04-02 17:59:13

解答

化简就行
(2x-3)(x-4)-(x+2)(x-3)≥x^2-8
(2x^2-11x+12)-(x^2-x-6)-x^2+8>=0
-10x+26>=0
x<=13/5