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化简后求值:(a+3/a^2-4+a/6-a-a^2)除以4a+9/5a-10,其中x=8
人气:337 ℃ 时间:2019-08-18 03:33:03
解答
[(a+3)/(a+2)(a-2)-a/(a+3)(a-2)]×5(a-2)/(4a+9)=[(a+3)/(a+2)-a/(a+3)] ×5/(4a+9)=[(a+3)²-a(a+2)]/(a+2)(a+3)×5/(4a+9)=(4a+9)/(a+2)(a+3)×5/(4a+9)=5/(a+2)(a+3)当a=8时原式=5/10×11=1/22
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