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f(x)=根号3sin^2x+sinxcosx-根号3/2
人气:214 ℃ 时间:2019-10-11 12:37:09
解答
f(x)=根号3sin^2x+sinxcosx-根号3/2
=sinxcosx-√3/2*(1-2sin²x)
=(1/2)sin2x-(√3/2)cos2x
=sin(2x)*cos(π/3)-cos(2x)sin(π/3)
=sin(2x-π/3)
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