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1) tan5π/12 2)1/sin10°-√3/cos10º
人气:161 ℃ 时间:2020-04-10 07:39:17
解答
1) tan5π/12 =cotπ/12=(1+cosπ/6)/sinπ/6=2+sqrt(3)【sqrt表示根号】2)1/sin10°-√3/cos10º =(cos10º-sqrt(3)sin10°)/(sin10°cos10º )=4(sin30°cos10º-cos30°sin10°)/(2sin10°cos1...
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