（1）原式=lim(x->0){e^[ln(x+e^x)/x]}=e^{lim(x->0)[ln(x+e^x)/x]}=e^{lim(x->0)[(1+e^x)/(x+e^x)]} (0/0型极限,应用罗比达法则)=e^[(1+1)/(0+1)]=e²；（2）原式=lim(x->π/2){e^[2cosxln(tanx)]}=e^{lim(x->...