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f(x)=sin^4x+2√3sinxcosx-cos^4x化简
人气:154 ℃ 时间:2020-06-07 12:22:46
解答
原式=sinx^4-cosx^4+2√3sinxcosx
=sinx^2-cosx^2+√3sin2x
=1-cos2x/2-1+cos2x/2+√3sin2x
=-cos2x+√3sin2x
=2sin(2x-π/6)
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