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设x是根号下(3+根号5)- 根号下(3-根号5)的小数部分,y是根号下(6+3倍根号5)- 根号下(6-3倍根号5)的小数部分.求2/y-1/x
是我搞错了,不好意思,后面的是根号下(6+3倍根号3)- 根号下(6-3倍根号3)
人气:230 ℃ 时间:2020-08-25 07:56:15
解答
题目有问题,6-3√5 < 0,√(6 - 3√5)在实数范围内无意义.这里只做前一半,后一半请查清题目后接着问或仿照做.
设X = √(3+√5) - √(3 -√5)
X= √[(6+ 2√5)/2] - √[(6 - 2√5)/2]
= √[(5 + 2√5 + 1)/2] - √[(5- 2√5 + 1)/2]
= √[(√5 + 1)²/2] - √[(√5 - 1)²/2]
= (√5 + 1)/√2 - (√5 - 1)/√2
= (√5+ 1 - √5 + 1)/√2
= 2/√2 = √2
1 < X < 2
x = X - 1 = √2 - 1
1/x = 1/(√2 - 1) = (√2+ 1)/[(√2-1)(√2 + 1)] = √2 + 1
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