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tan70cos10(根3tan20-1)
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人气:354 ℃ 时间:2020-10-02 06:02:26
解答
tan70cos10(√3tan20-1)
=tan70cos10(√3sin20/cos20-1)
=tan70cos10((√3sin20-cos20)/cos20)
=tan70cos10(2sin(20-30)/cos20)
=-tan70[2cos10sin10/cos20]
=-tan70[sin20/cos20]
=-cot20tan20
=-1
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