原式=2mx^2-x^2+3x+1-5x^2+4y^2-3x
=(2m-6)x^2+1+4y^2
与x无关则系数为0
2m-6=0
m=3
所以2-[3m^2+(4m-5)+m]
=2-3m^2-4m+5-m
=-3m^2-5m+7
=-27-15+7
=-35