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化简:2a-b-c/(a-b)(a-c) + 2b-a-c/(b-c)(b-a) + 2c-a-b/(c-b)(c-a)
人气:169 ℃ 时间:2020-04-16 11:06:38
解答
(2a-b-c)/[(a-b)(a-c)] + (2b-a-c)/[(b-c)(b-a)] + (2c-a-b)/[(c-b)(c-a)]=[(a-b)+(a-c)]/[(a-b)(a-c)] +[(b-a)+(b-c)]/[(b-c)(b-a)] +[(c-a)+(c-b)]/[(c-b)(c-a)]=[(1/(a-b))+(1/(a-c))]+[(1/(b-c))+(1/(b-a))]+[(1...
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