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y=-2x/(1+x2)^2的导数怎么求?
(求详解)
人气:164 ℃ 时间:2020-10-01 18:45:14
解答
y=-2x/(1+x^2)^2
y' =-2[(1+x^2)^2 - 4x^2.(1+x^2) ]/(1+x^2)^4
=2(3x^4+2x^2 -1)/(1+x^2)^4
=2(3x^2-1)(x^2+1)/(1+x^2)^4
=2(3x^2-1)/(1+x^2)^3
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