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因式分解: -8a²b³c+16a²bc³; a²-1+b²-2ab
人气:339 ℃ 时间:2020-05-21 03:23:36
解答

-8a²b³c+16a²bc³
=-8a²bc(b²-2c²)
a²-1+b²-2ab
=(a²-2ab+b²)-1
=(a-b)²-1²
=(a-b-1)(a-b+1)
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