√x(√x+2√y)=√y(6√x+5√y)(√x)²-4√(xy)-5(√y)²=0(√x-5√y)(√x+√y)=0∴√x=5√y √x=-√y 舍去原式=[(√x)²-3√x√y+2y]/[(√x)²+√x√y-6y]=(25y-15y+2y)/(25y+5y-6y)=12y/24y=1/2...