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(x²-6x+9)÷x+3分之x²-9x+18,计算
人气:388 ℃ 时间:2020-02-06 05:39:47
解答
(x²-6x+9)÷x+3分之x²-9x+18,
=(x²-6x+9)×(x+3)/(x²-9x+18)
=(x-3)²(x+3)/[(x-3)(x-6)]
=(x-3)(x+3)/(x-6)
=(x²-9)/(x-6)
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