请问“(x+2)/(x+1)-(x+3)/(x+2)-(x-4)/(x-3)+(x-5)/(x-4)”怎样做,急用
人气:190 ℃ 时间:2020-05-20 12:45:12
解答
分子都比分母大1,所以先整理为:原式=(x+2)/(x+1)-(x+3)/(x+2)-(x-4)/(x-3)+(x-5)/(x-4)=[1+1/(x+1)]-[1+1/(x+2)]-[1-1/(x-3)]+[1-1/(x-4)]=1+1/(x+1)-1-1/(x+2)-1+1/(x-3)+1-1/(x-4)=[1/(x+1)+1/(x-3)]-[1/...
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