A(g) + 2B(g) = 3C(g)
(2)求用A来表示的反应的平均速率:
v(A) = - △C(A) / △t = -(0.8-1.0) / 2 = 0.1 (mol/L·min)
(1)2min末B,C的浓度
求B的浓度,设为x:
v(B) = 2v(A) = - △C(B) / △t = - (x - 1.2) / 2 = 0.1*2
x = 0.8 (mol/L)
求C的浓度,设为y:
v(C) = 3v(A) = △C(C) / △t = (y-0) / 2 = 0.1*3
y = 0.6 (mol/L)