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∫(x∧4/x∧2+1)dx
人气:292 ℃ 时间:2020-05-13 22:53:26
解答
∫(x^4/(x^2+1))dx =∫((x^4-1+1)/(x^2+1))dx =∫((x^4-1)/(x^2+1))dx +∫(1/(x^2+1))dx =∫((x^2-1)*(x^2+1)/(x^2+1))dx + arctan x +c=∫(x^2-1)dx + arctan x +c=x^3/3-x+arctan x +c
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