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设y=[cos (1/x)]^3,则dy=
如题………………
人气:495 ℃ 时间:2020-06-21 07:34:26
解答
y'=3[cos(1/x)]^2*[cos(1/x)]'..=3[cos(1/x)]^2*[-sin(1/x)]*(1/x)'..=3[cos(1/x)]^2*[-sin(1/x)]*(-1/x^2)..=3[cos(1/x)]^2[sin(1/x)]/x^2所以dy=3[cos(1/x)]^2[sin(1/x)]/x^2 dx
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