初一数学题(x+2y)^2(x^2+4y^2)^2(x-2y)^2-[X^4-(2y^4)^2]^2(x+2y)^2(x^2+4y_数学解答

初一数学题(x+2y)^2(x^2+4y^2)^2(x-2y)^2-[X^4-(2y^4)^2]^2
(x+2y)^2(x^2+4y^2)^2(x-2y)^2-[X^4-(2y^4)^2]^2要步骤

人气：301 ℃　时间：2020-04-04 20:27:19

解答

(2y^4)^2应该是(4y^2)^2
原式=[(x+2y)(x-2y)]^2(x^4+4y^2)]^2-(x^4-16y^4)^2
=(x^2-4y^2)^2(x^4+4y^2)]^2-(x^4-16y^4)^2
=(x^4-16y^4)^2-(x^4-16y^4)^2
=0