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若logx表示log10x(10为底数),且log(5x^2)=a,则log(4/x^2)=
应该是若logx表示log底数10x,且log(5x^2)=a,则log(4/x^4)=
人气:350 ℃ 时间:2020-05-16 17:36:03
解答
log(5x^2)=a
log5+logx^2=a
logx^2=a-log5
log(4/x^2)
=log4-logx^2
=log4-a+log4
=lig20-a
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