八下阿基米德原理,
将一个质量为89克的铜块挂在弹簧测力计上,浸没在某种液体中时,弹簧测力计的示数减小0.08N,这种液体的密度是多少?
人气：182 ℃ 时间：2020-04-15 12:31:04
解答
因为浸没
∴V=M/P=89g/8.9g/cm三次方=10cm三次方(P=密度)
F浮=0.089N-0.08N=0.009N
F浮=PgV=P*10*10（-6次方）=0.009N
∴P=0.9g/cm（三次方）
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