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阶乘数列求和
1/2!+2/3!+3/4!+…+n/(n+1)!为多少?
人气:408 ℃ 时间:2019-10-11 07:35:01
解答
由k/(k+1)!=(k+1-1)/(k+1)!=1/k!-1/(k+1)!,故得
1/2!+2/3!+3/4!+…+n/(n+1)!
=1/1!-1/2!+1/2!-1/3!+1/3!-1/4!+…+1/n!-1/(n+1)!
=1-1/(n+1)!
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