> 其他 >
高一三角函数化简求值
(1) 2sin160°-cos170°-tan160°sin170°=
(2) cot20°cos10°+根号3sin10°tan70°-2cos40°=
人气:281 ℃ 时间:2020-07-06 10:52:57
解答
原式=2sin20°+cos10°+tan20°sin10°
=(2sin20°cos20°+cos10°cos20°+sin20°sin10°)/cos20°
=(sin40°+cos10°)/cos20°
=(cos50°+cos10°)/cos20°
=(cos30°cos20°)/cos20°
=cos30°
=√3/2
原式=tan70°(cos10°+√3sin10°)-2cos40°
=2tan70°sin(10°+30°)-2cos40°
=2(tan70°sin 40°-cos40)°
=2(cos20°sin40°-sin20°cos40°)/sin20°
=2sin20°/sin20°
=2
不明白连我Baidu Hi,
推荐
猜你喜欢
© 2024 79432.Com All Rights Reserved.
电脑版|手机版