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{(m+n)²—4(m—n)²}÷(3n—m)=?
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人气:434 ℃ 时间:2020-05-13 23:35:25
解答
{(m+n)²—4(m—n)²}÷(3n—m)
=(m^2+2mn+n^2-4m^2+8mn-4n^2)/(3n-m)
=-(3m^2-10mn+3n^2)/(3n-m)
=-(3m-n)(m-3n)/(3n-m)
=3m-n
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