当a=1/3时,求多项式5a²-5a+4-3a²+6a-5的值,用两种方法计算:
(1)将a的值直接代入多项式中计算;
(2)先化简多项式,再将a的值代入计算
人气:221 ℃ 时间:2019-10-23 09:01:56
解答
(1)原式=5×(1/3)²-5×1/3+4-3×(1/3)²+6×1/3-5
=-4/9
(2)原式=2a²+a-1
=2×(1/3)²+1/3-1
=-4/9可以把过程写详细点儿么?谢了(1)当a=1/3时原式=5×(1/3)²-5×1/3+4-3×(1/3)²+6×1/3-5=5/9-5/3+4-1/4+2-5=-4/9(2)原式=2a²+a-1 当a=1/3时 原式=2×(1/3)²+1/3-1 =2/9+1/3-1 =-4/9亲爱的我想把加加减减的那些让你写清楚点儿,因为我实在不会加减,5×(1/3)²-5×1/3+4-3×(1/3)²+6×1/3-5=5/9-5/3+4-1/3+2-5=5/9-15/9+4-3/9-3=-13/9+1-4/9 2×(1/3)²+1/3-1 =2/9+1/3-1 =2/9+3/9-1=5/9-1=-4/9
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