[(3x^2-14x+14)-(x^2-6x+8)]/(x^2-6x+8)≥0
(x^2-4x+3)/(x^2-6x+8)≥0
(x-1)(x-3)/[(x-2)(x-4)]≥0
(x-1)(x-3)/[(x-2)(x-4)]=0四个实数根是
1,2,3,4
解是:x≤1,2＜x≤3,x＞4