水平渐近线：limx→∞e1x2arctanx2+x−1(x+1)(x−2)=limx→∞e1x2limx→∞arctanx2+x−1(x+1)(x−2)＝1•arctan1＝π4所以有水平渐近线y=π4垂直渐近线：limx→0e1x2arctanx2+x−1(x+1)(x−2)＝+∞limx→1−e1x2arct...